- 新增现代 C++ 教程的 Preface 章节,包括英文和中文版本 - 添加 C++ Primer 练习代码 - 新增 Learn C++ 教程的 C++ 开发简介章节 - 添加头文件解析文档 - 更新 mkdocs.yml,包含新教程的目录结构 - 修改项目设置,使用 Python 3.10环境
418 lines
8.6 KiB
Markdown
418 lines
8.6 KiB
Markdown
---
|
||
sort: 8
|
||
---
|
||
|
||
# IO库
|
||
|
||
## 练习8.1
|
||
> 编写函数,接受一个`istream&`参数,返回值类型也是`istream&`。此函数须从给定流中读取数据,直至遇到文件结束标识时停止。它将读取的数据打印在标准输出上。完成这些操作后,在返回流之前,对流进行复位,使其处于有效状态。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
std::istream& func(std::istream &is)
|
||
{
|
||
std::string buf;
|
||
while (is >> buf)
|
||
std::cout << buf << std::endl;
|
||
is.clear();
|
||
return is;
|
||
}
|
||
```
|
||
|
||
## 练习8.2
|
||
> 测试函数,调用参数为`cin`。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <iostream>
|
||
using std::istream;
|
||
|
||
istream& func(istream &is)
|
||
{
|
||
std::string buf;
|
||
while (is >> buf)
|
||
std::cout << buf << std::endl;
|
||
is.clear();
|
||
return is;
|
||
}
|
||
|
||
int main()
|
||
{
|
||
istream& is = func(std::cin);
|
||
std::cout << is.rdstate() << std::endl;
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
## 练习8.3
|
||
> 什么情况下,下面的`while`循环会终止?
|
||
|
||
```cpp
|
||
while (cin >> i) /* ... */
|
||
```
|
||
|
||
解:
|
||
|
||
遇到文件结束符、或者IO流错误,或读入了无效数据。
|
||
|
||
## 练习8.4
|
||
> 编写函数,以读模式打开一个文件,将其内容读入到一个`string`的`vector`中,将每一行作为一个独立的元素存于`vector`中。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
void ReadFileToVec(const string& fileName, vector<string>& vec)
|
||
{
|
||
ifstream ifs(fileName);
|
||
if (ifs)
|
||
{
|
||
string buf;
|
||
while (getline(ifs, buf))
|
||
vec.push_back(buf);
|
||
}
|
||
}
|
||
```
|
||
|
||
## 练习8.5
|
||
> 重写上面的程序,将每个单词作为一个独立的元素进行存储。
|
||
解:
|
||
|
||
```cpp
|
||
void ReadFileToVec(const string& fileName, vector<string>& vec)
|
||
{
|
||
ifstream ifs(fileName);
|
||
if (ifs)
|
||
{
|
||
string buf;
|
||
while (ifs >> buf)
|
||
vec.push_back(buf);
|
||
}
|
||
}
|
||
```
|
||
|
||
## 练习8.6
|
||
> 重写7.1.1节的书店程序,从一个文件中读取交易记录。将文件名作为一个参数传递给`main`。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <fstream>
|
||
#include <iostream>
|
||
|
||
#include "../ch07/ex7_26.h"
|
||
using std::ifstream; using std::cout; using std::endl; using std::cerr;
|
||
|
||
int main(int argc, char **argv)
|
||
{
|
||
ifstream input(argv[1]);
|
||
|
||
Sales_data total;
|
||
if (read(input, total))
|
||
{
|
||
Sales_data trans;
|
||
while (read(input, trans))
|
||
{
|
||
if (total.isbn() == trans.isbn())
|
||
total.combine(trans);
|
||
else
|
||
{
|
||
print(cout, total) << endl;
|
||
total = trans;
|
||
}
|
||
}
|
||
print(cout, total) << endl;
|
||
}
|
||
else
|
||
{
|
||
cerr << "No data?!" << endl;
|
||
}
|
||
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
## 练习8.7
|
||
> 修改上一节的书店程序,将结果保存到一个文件中。将输出文件名作为第二个参数传递给`main`函数。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <fstream>
|
||
#include <iostream>
|
||
|
||
#include "../ch07/ex7_26.h"
|
||
using std::ifstream; using std::ofstream; using std::endl; using std::cerr;
|
||
|
||
int main(int argc, char **argv)
|
||
{
|
||
ifstream input(argv[1]);
|
||
ofstream output(argv[2]);
|
||
|
||
Sales_data total;
|
||
if (read(input, total))
|
||
{
|
||
Sales_data trans;
|
||
while (read(input, trans))
|
||
{
|
||
if (total.isbn() == trans.isbn())
|
||
total.combine(trans);
|
||
else
|
||
{
|
||
print(output, total) << endl;
|
||
total = trans;
|
||
}
|
||
}
|
||
print(output, total) << endl;
|
||
}
|
||
else
|
||
{
|
||
cerr << "No data?!" << endl;
|
||
}
|
||
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
## 练习8.8
|
||
> 修改上一题的程序,将结果追加到给定的文件末尾。对同一个输出文件,运行程序至少两次,检验数据是否得以保留。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <fstream>
|
||
#include <iostream>
|
||
|
||
#include "../ch07/ex7_26.h"
|
||
using std::ifstream; using std::ofstream; using std::endl; using std::cerr;
|
||
|
||
int main(int argc, char **argv)
|
||
{
|
||
ifstream input(argv[1]);
|
||
ofstream output(argv[2], ofstream::app);
|
||
|
||
Sales_data total;
|
||
if (read(input, total))
|
||
{
|
||
Sales_data trans;
|
||
while (read(input, trans))
|
||
{
|
||
if (total.isbn() == trans.isbn())
|
||
total.combine(trans);
|
||
else
|
||
{
|
||
print(output, total) << endl;
|
||
total = trans;
|
||
}
|
||
}
|
||
print(output, total) << endl;
|
||
}
|
||
else
|
||
{
|
||
cerr << "No data?!" << endl;
|
||
}
|
||
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
|
||
## 练习8.9
|
||
> 使用你为8.1.2节第一个练习所编写的函数打印一个`istringstream`对象的内容。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <iostream>
|
||
#include <sstream>
|
||
using std::istream;
|
||
|
||
istream& func(istream &is)
|
||
{
|
||
std::string buf;
|
||
while (is >> buf)
|
||
std::cout << buf << std::endl;
|
||
is.clear();
|
||
return is;
|
||
}
|
||
|
||
int main()
|
||
{
|
||
std::istringstream iss("hello");
|
||
func(iss);
|
||
return 0;
|
||
}
|
||
|
||
```
|
||
|
||
## 练习8.10
|
||
> 编写程序,将来自一个文件中的行保存在一个`vector`中。然后使用一个`istringstream`从`vector`读取数据元素,每次读取一个单词。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <iostream>
|
||
#include <fstream>
|
||
#include <sstream>
|
||
#include <vector>
|
||
#include <string>
|
||
|
||
using std::vector; using std::string; using std::ifstream; using std::istringstream; using std::cout; using std::endl; using std::cerr;
|
||
|
||
int main()
|
||
{
|
||
ifstream ifs("../data/book.txt");
|
||
if (!ifs)
|
||
{
|
||
cerr << "No data?" << endl;
|
||
return -1;
|
||
}
|
||
|
||
vector<string> vecLine;
|
||
string line;
|
||
while (getline(ifs, line))
|
||
vecLine.push_back(line);
|
||
|
||
for (auto &s : vecLine)
|
||
{
|
||
istringstream iss(s);
|
||
string word;
|
||
while (iss >> word)
|
||
cout << word << endl;
|
||
}
|
||
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
## 练习8.11
|
||
> 本节的程序在外层`while`循环中定义了`istringstream`对象。如果`record`对象定义在循环之外,你需要对程序进行怎样的修改?重写程序,将`record`的定义移到`while`循环之外,验证你设想的修改方法是否正确。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <iostream>
|
||
#include <sstream>
|
||
#include <string>
|
||
#include <vector>
|
||
using std::vector; using std::string; using std::cin; using std::istringstream;
|
||
|
||
struct PersonInfo {
|
||
string name;
|
||
vector<string> phones;
|
||
};
|
||
|
||
int main()
|
||
{
|
||
string line, word;
|
||
vector<PersonInfo> people;
|
||
istringstream record;
|
||
while (getline(cin, line))
|
||
{
|
||
PersonInfo info;
|
||
record.clear();
|
||
record.str(line);
|
||
record >> info.name;
|
||
while (record >> word)
|
||
info.phones.push_back(word);
|
||
people.push_back(info);
|
||
}
|
||
|
||
for (auto &p : people)
|
||
{
|
||
std::cout << p.name << " ";
|
||
for (auto &s : p.phones)
|
||
std::cout << s << " ";
|
||
std::cout << std::endl;
|
||
}
|
||
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
## 练习8.12
|
||
> 我们为什么没有在`PersonInfo`中使用类内初始化?
|
||
|
||
解:
|
||
|
||
因为这里只需要聚合类就够了,所以没有必要在`PersionInfo`中使用类内初始化。
|
||
|
||
## 练习8.13
|
||
> 重写本节的电话号码程序,从一个命名文件而非`cin`读取数据。
|
||
|
||
解:
|
||
|
||
```cpp
|
||
#include <iostream>
|
||
#include <sstream>
|
||
#include <fstream>
|
||
#include <string>
|
||
#include <vector>
|
||
|
||
using std::vector; using std::string; using std::cin; using std::istringstream;
|
||
using std::ostringstream; using std::ifstream; using std::cerr; using std::cout; using std::endl;
|
||
using std::isdigit;
|
||
|
||
struct PersonInfo {
|
||
string name;
|
||
vector<string> phones;
|
||
};
|
||
|
||
bool valid(const string& str)
|
||
{
|
||
return isdigit(str[0]);
|
||
}
|
||
|
||
string format(const string& str)
|
||
{
|
||
return str.substr(0,3) + "-" + str.substr(3,3) + "-" + str.substr(6);
|
||
}
|
||
|
||
int main()
|
||
{
|
||
ifstream ifs("../data/phonenumbers.txt");
|
||
if (!ifs)
|
||
{
|
||
cerr << "no phone numbers?" << endl;
|
||
return -1;
|
||
}
|
||
|
||
string line, word;
|
||
vector<PersonInfo> people;
|
||
istringstream record;
|
||
while (getline(ifs, line))
|
||
{
|
||
PersonInfo info;
|
||
record.clear();
|
||
record.str(line);
|
||
record >> info.name;
|
||
while (record >> word)
|
||
info.phones.push_back(word);
|
||
people.push_back(info);
|
||
}
|
||
|
||
for (const auto &entry : people)
|
||
{
|
||
ostringstream formatted, badNums;
|
||
for (const auto &nums : entry.phones)
|
||
if (!valid(nums)) badNums << " " << nums;
|
||
else formatted << " " << format(nums);
|
||
if (badNums.str().empty())
|
||
cout << entry.name << " " << formatted.str() << endl;
|
||
else
|
||
cerr << "input error: " << entry.name
|
||
<< " invalid number(s) " << badNums.str() << endl;
|
||
}
|
||
|
||
return 0;
|
||
}
|
||
```
|
||
|
||
## 练习8.14
|
||
> 我们为什么将`entry`和`nums`定义为`const auto&`?
|
||
|
||
解:
|
||
|
||
它们都是类类型,因此使用引用避免拷贝。
|
||
在循环当中不会改变它们的值,因此用`const`。 |